$\left(\frac{1}{2}-6\right)^3$
$\left(x-3\right)^2+4x\left(x-2\right)=27+5x$
$8c^9+64d^3$
$\left(1+\frac{1}{x}\right)^x$
$\int\left(2\tan\left(3x\right)-\cot\left(3x\right)\right)^2dx$
$tan\left(x\right)\left(1-sin^2\left(x\right)\right)$
$\int e^{-0.05x}dx$
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