$4m^2-4m+1$
$\lim_{x\to0}\left(\frac{\sin\left(x-1\right)}{x^2-3x+2}\right)$
$x\ln9+x\ln12=x\ln16$
$3m^2-16m+5=0$
$196x^2b^2-25a^2$
$\left(x+3\right)+\left(x+5\right)$
$\left(3y+6x\right)\left(3y-6x\right)$
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