$10x-2x+6x-4x$

$\int\left(x^2\cdot\left(2x^3-1\right)\right)dx$

$72=-8x$

$\lim_{x\to0}\left(\frac{1-\cos\left(x^2\right)}{x^3\sin\left(x\right)}\right)$

$-\left\{-8-\left[-4+\left(-4-7\right)\right]-34+\left(-2-3\right)\right\}$

$72r^6-2s^2$

$\frac{tan\:x\:\left(sin\:x\right)}{sec\left(x\right)}=1+cosx$