$\int\frac{\left(x^2\:+x\:+2\right)}{\left(3x^3-x^2+3x+1\right)}dx$
$xy'=1-x^2+y^2-x^2y^2$
$x^2-2i+2=0$
$\int\left(\frac{3}{50-2t}\right)dt$
$\frac{x^2-4x+2}{x^2-4}$
$5x^2-5$
$\frac{-36wx^6y}{64x^2y^6}$
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