$4x^2+4\left(x+x\right)\left(x^2-x^2+x\right)$
$-8+\left(-11\right)-\left(-8\right)$
$-7\left(2n-3\right)+5\left(n+9\right)$
$\lim_{x\to\infty}\left(\frac{2e^{2x}-2}{x^2+x}\right)$
$\frac { ( x + 2 ) ^ { 3 } } { x + 2 }$
$\left(x+7\right)\left(x-5\right)-\left(x+2\right)^2$
$x>2x-3$
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