$6-\frac{1}{2}\cdot12$
$\frac{-4x-1}{3}>1-2x$
$\int\left(\frac{3x+6}{x^2+4x-1}\right)dx$
$\ln4x^3$
$\left(k-7\right)\left(k+4\right)$
$\lim_{x\to3}\left(5x^2-2x+7\right)$
$\frac{dy}{dx}=ysin\left(4x\right)$
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