$16\cdot40$
$6x^2+5x-6$
$3\left(10\right)^4\:-\:3\left(10\right)^3\:-\left(10\right)^2\:+\:3\left(10\right)\:-\:1\:$
$3x^2+5x+9+2x^2+3x+1$
$\frac{2\cos\left(x\right)}{1-\sin^2\left(x\right)}$
$\lim_{x\to0}\left(3x\right)^{\cos\left(x\right)x}$
$16x^2+48xy^2+36y^4$
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