$\lim_{x\to\infty}ln\left(\frac{\left(6+x\right)}{5+4x^2}\right)$
$-1+logx=\frac{-1-logx}{logx+1}$
$2x^3+3x^2-3x-2$
$\lim_{x\to\infty}\left(\frac{e^x+x}{e^x+x^2}\right)$
$\left(10m-6\right)\left(-2\right)$
$7x+5=-100$
$n^2-3+3n+2n^2+n$
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