$\lim_{x\to\infty}\left(\frac{x^2+3x+6}{6-x}\right)$
$\:x^2+3x+3>\:0$
$\frac{7x^2-3x+1}{x-1}$
$\frac{dy}{dx}=0.08x^2$
$\lim_{x\to0}\left(\frac{\sqrt{x+1}-1}{\sqrt{x}}\right)$
$\frac{dy}{dx}=81e^{5x}y^2+36e^{5x}$
$\frac{d^2t}{dx^2}=0$
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