$\lim_{x\to0}\left(\frac{2}{x^2}\right)$
$1^2-16$
$4x^2-8x=0\:$
$\sqrt{6x^2y}\cdot\sqrt{6x^4}y$
$5-\left|7-2\left(1-9\right)-3+12\right|+4$
$1100+1.298$
$\lim_{x\to0}\left(\frac{4}{x^3-2}\right)$
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