limx→∞(12ln(x4−1)+x2)\lim_{x\to\infty}\left(\frac{1}{2}ln\left(\sqrt{x^4-1}\right)+x^2\right)x→∞lim(21ln(x4−1)+x2)
y′=sin yy'=sin\:yy′=siny
(2m2−10y)(2m2+10)\left(2m^2-10y\right)\left(2m^2+10\right)(2m2−10y)(2m2+10)
cotx=cosxcscx\cot x=\cos x\csc xcotx=cosxcscx
c2−25c^2-25c2−25
8a2b−4b28a^2b-4b^28a2b−4b2
(x2−y2)5( x ^ { 2 } - y ^ { 2 } ) ^ { 5 }(x2−y2)5
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