$32\cdot19$

$\left(m\:-\:1\right)\:\left(m^2\:+\:m\:+\:1\right)\:=\:m^3\:-\:1$

$4x^4y^2-28x^3y^3+40x^2y^4-48xy^5$

$\left(2m^2-3n\right)^5$

$\int\left(\frac{\cos\left(x\right)}{\left(1-cos^2\left(x\right)\right)^6}\right)dx$

$\frac{16x^4-y^{12}}{2x-2y}$

$100m^2-40m+2^2$