$2x^2+11x-21=0$
$\lim_{x\to\infty}\left(\frac{9x}{9x+2}\right)^{8x}$
$\left(4^5\right)^2\left(4^3\right)$
$y^2+3x=8$
$\left(2.5e\right)\left(4\right)$
$\frac{2x^3-65x-45}{x+5}$
$\frac{-5x}{-10x^5y^8}$
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