$\left(\sqrt{5}-2\right)-\left(\sqrt{5}+2\right)$
$cot^2x-3=0$
$1+m^7$
$\frac{3\cdot\sqrt[3]{\left(64\right)\left(2\right)^3\left(3\right)^6}}{\left(2\right)\left(\frac{1}{2}\right)}$
$64x^2-70x+25$
$\:\left(4a+3b\right)\left(4a-3b\right)$
$\left(d+1\right)\left(d-1\right)$
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