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Exercise

((20m2n−mn)9x2−30xy+25y2)(n2+nm2−n2)\left(\frac{\left(20m^2n-mn\right)}{9x^2-30xy+25y^2}\right)\left(\frac{n^2+n}{m^2-n^2}\right)

Step-by-step Solution

1

Multiplying fractions 20m2n−mn9x2−30xy+25y2×n2+nm2−n2\frac{20m^2n-mn}{9x^2-30xy+25y^2} \times \frac{n^2+n}{m^2-n^2}

(20m2n−mn)(n2+n)(9x2−30xy+25y2)(m2−n2)\frac{\left(20m^2n-mn\right)\left(n^2+n\right)}{\left(9x^2-30xy+25y^2\right)\left(m^2-n^2\right)}

Final answer to the exercise

(20m2n−mn)(n2+n)(9x2−30xy+25y2)(m2−n2)\frac{\left(20m^2n-mn\right)\left(n^2+n\right)}{\left(9x^2-30xy+25y^2\right)\left(m^2-n^2\right)}

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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((20m2n−mn)9x2−30xy+25y2 )(n2+nm2−n2 )
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