$\int\left(\frac{1}{x^4\sqrt{x^2-36}}\right)dx$
$\left(+16\right)-\left(-4\right)$
$1-1\cdot4\left(4\left(6-3+1\right)-1\right)$
$3x^2-2,\:5x+0,\:5$
$\frac{24.57}{4.50}$
$\int\frac{2}{\left(\sqrt{1-4x^2}\right)}dx$
$\frac{dy}{dx}=\left(y^2-1\right)x$
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