$\left(3u^{-1}v^3\right)^4$
$\int\frac{1}{x^2+2x-9}dx$
$x^{2}+14x-49$
$2^{-1}\left(2^4\right)$
$4^2\cdot4^6$
$5x\sqrt[3]{16x^4}$
$\frac{b^2-8+16}{b^2-16}$
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