$\int3x^3\left(2x^4+3\right)^3dx$
$i'=\frac{1+2t}{2i}$
$\left(-15\right)-\left(-20\right)$
$\int\frac{4\text{sen}3x}{3e^{2x}}dx$
$tan\:xsen\:^3ydx\:+sec^3\:xcos\:ydy\:=\:0$
$5m^2-15m^3$
$24+3^27^32$
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