$\frac{dy}{dx}=\left(2x-1\right)\left(y+1\right)$

$\frac{dv}{dt}=\frac{256-v^2}{8}$

$\left(2a+3b-c\right)^2$

$\left(2-x\right).\left(3x+1\right)$

$\frac{1}{4}m+\frac{3}{4}-\frac{3}{8}\left(m+1\right)$

$14\left(m\:-\:2\right)\:+\:m\:-\:2\:=\:45$

$\log_{2x}\left(16x+9\right)=2$