$\left(2x-1\right)\left(-4x+2\right)$
$\frac{3}{x-2}<\frac{1}{x}$
$-3y\cdot2z$
$\left(+61\right)\cdot\left(-98\right)$
$cos\:x\:\left(tan\:x\:+cot\:x\:\right)=cos\:x$
$\frac{3\cdot\left(-2\right)\left(-3\right)\left(-1\right)}{\left(-2\right)\left(-1\right)}$
$\frac{\left(x^3-6x^2-x+8\right)}{\left(x^2-7x+6\right)}$
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