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$\int_1^{\infty}\left(\frac{5x+7}{8x^2+6x+1}\right)dx$

Final answer to the exercise

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Other solved exercises

$\frac{dy}{dx}+y=0.3x^2$

$6x^2+7x+1$

$\frac{x}{4}+8=41$

$\frac{dy}{dx}=\frac{2x+3}{y^3}$

$-8\left(3x-7\right)+5x$

$100x^6-1$

$84+2$
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