$\frac{dy}{dt}=\frac{t}{y\left(1-t^2\right)};\:y\left(0\right)=1$
$2x+4y=-16$
$2^{-2}\cdot2^3\cdot2^4$
$2m^2-7m+3$
$\left(-4b+5\right)^2$
$-8\:\cdot5$
$-4x-5<3x+2$
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