$12\cdot3+6$
$\sqrt{\frac{18}{2}}$
$12.7+3$
$6c+d=-2$
$\frac{-1+i}{i}$
$y'-\frac{3}{x}\:y\:=\:x^3\:cos\:x$
$\left(x-y\right)^2\:\left(3x-2y\right)$
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