$\frac{d}{dx}2x^3y-3xy^3=5$
$\:\left(-7a-6\right)+\left(-5a+3\right)$
$\int\:\frac{x^2}{2x^3-6}dx$
$\sin42=\frac{5}{3\left(x\right)}$
$\lim_{x\to\infty}\left(\sqrt{x^2+8x}-x\right)$
$\frac{d^2}{dx^2}\left(x-3xy+y=0\right)$
$\frac{12}{\sqrt{t}-\sqrt{15}}$
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