$\left(10\right)-\left(6\right)-\left(-8\right)-\left(-7\right)$
$\left(x-0.4\right)\left(x-0.2\right)$
$x^2+2x-10$
$\int\frac{x^2+3x+7}{x+1}dx$
$10\:+\:4t\:-\:6y$
$-8+3+1-6-1+5-9+10-7$
$3\left(x-4\right)-7\left(x+2\right)=-2\left(x+18\right)$
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