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(112)−1\left(\frac{1}{12}\right)^{-1}(121)−1
x+x2x+\frac{x}{2}x+2x
2z=−3z−1\frac{2}{z}=\frac{-3}{z}-1z2=z−3−1
2−3(8)2-3\left(8\right)2−3(8)
7x2 + 10x + 5 x − 3 \:\frac{\:7x^2\:+\:10x\:+\:5\:\:}{x\:-\:3}\:x−37x2+10x+5
400−36v2400-36v^2400−36v2
−2tu5v10(4t2v)2-\frac{2tu^5v^{10}}{\left(4t^2v\right)^2}−(4t2v)22tu5v10
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