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$\left(8x^3+9m^3\right)^2$
$\frac{dy}{dx}=\left(\frac{y+1}{xy+x}\right)$
$y=\left[\frac{\left(3x+4\right)}{4x+3}\right]^4$
$\int_{-1}^33xdx$
$14-1$
$\left(3x-1\right)^2\:\le\:9\left(x^2-4\right)$
$y+4+x+8$
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