$10c^2+\:35cd-45d^2$
$.5h^4\cdot4\left(h^2\right)^8$
$\left(2a+b-c\right)\left(2a+b+c\right)$
$x^2+9x+9$
$\frac{a^5}{a^{-3}}$
$12x-8>4x$
$5x\left(x+2\right)+6$
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