$\lim_{x\to0}\left(\frac{1+\left(\tan\:x\right)^2-\cos\left(2x\right)}{x\sin\left(x\right)}\right)$
$\left(x-7x^2y^3\right)$
$7\cdot1^2-1$
$+9\:-\:\left(-13\right)$
$\frac{dy}{dx}=y^3\sin\left(x\right)$
$\frac{b^{-4}}{b^{-1}\cdot b^0\cdot b}$
$-9y+2y$
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