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f(x)=(5(2x^4+3x^3-2.0x))/(3x^2+2)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫00.3569017825310408(5(2x4+3x3−2x)3x2+2)dx\int_0^{0.3569017825310408}\left(\frac{5\left(2x^4+3x^3-2x\right)}{3x^2+2}\right)dx

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Final answer to the exercise

10⋅0.356939+52⋅0.35692−7.1389+2023arctan⁡(0.356932)9+103ln⁡∣23∣−103ln⁡∣29⋅0.61822+23∣\frac{10\cdot 0.3569^{3}}{9}+\frac{5}{2}\cdot 0.3569^2-\frac{7.138}{9}+\frac{20\sqrt{\frac{2}{3}}\arctan\left(0.3569\sqrt{\frac{3}{2}}\right)}{9}+\frac{10}{3}\ln\left|\frac{2}{3}\right|-\frac{10}{3}\ln\left|\frac{2}{9}\cdot 0.6182^2+\frac{2}{3}\right|

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∫00.3569017825310408(5(2x4+3x3−2x)3x2+2 )dx
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