Integrate the function 6sin(2x)(20cos(2x)^2+16)^(1/2) from 0 to pi

 Exercise

\int_0^{\pi}\left(6\sin\left(2x\right)\cdot\sqrt{20\cos^2\left(2x\right)+16}\right)dx

-6\cdot \left(\frac{\frac{360.0034722}{321.9968944}\cos\left(2\pi \right)\sqrt{5\cdot \cos\left(2\pi \right)^2+4}}{\sqrt{5}}+\frac{4}{2\sqrt{5}}\ln\left|\frac{\sqrt{5\cdot \cos\left(2\pi \right)^2+4}}{2}+\frac{169.9705831}{152.0263112}\cos\left(2\pi \right)\right|- \left(\frac{\frac{360.0034722}{321.9968944}\cos\left(2\cdot 0\right)\sqrt{5\cdot \cos\left(2\cdot 0\right)^2+4}}{\sqrt{5}}+\frac{4}{2\sqrt{5}}\ln\left|\frac{\sqrt{5\cdot \cos\left(2\cdot 0\right)^2+4}}{2}+\frac{169.9705831}{152.0263112}\cos\left(2\cdot 0\right)\right|\right)\right)

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