$\lim_{x\to\infty}\left(\frac{4x+3}{\ln\left(2+4e^x\right)}\right)$

$\left(3a\right)^3\left(2a\right)^2$

$\left(2xy^2-5\right)dx+\left(2x^2y+6\right)dy=0$

$\frac{10\left(-30\right)}{6}$

$\int\frac{x^2+1}{2x^2+x-3}dx$

$a^4+4a^2+4$

$\lim_{x\to0}\left(\frac{-4\left(0\right)}{\sqrt{2-\left(0\right)}-\sqrt[4]{4}}.\right)$