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∫x+1tan⁡(x)(sin⁡(u)u)du\int_{x+1}^{\tan\left(x\right)}\left(\frac{\sin\left(u\right)}{u}\right)du

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Final answer to the exercise

tan⁡(x)+−tan⁡(x)318+tan⁡(x)5600+−tan⁡(x)735280−x−1+x3+3x2+3x+118+−(x+1)5600+(x+1)735280\tan\left(x\right)+\frac{-\tan\left(x\right)^3}{18}+\frac{\tan\left(x\right)^5}{600}+\frac{-\tan\left(x\right)^7}{35280}-x-1+\frac{x^3+3x^2+3x+1}{18}+\frac{-\left(x+1\right)^5}{600}+\frac{\left(x+1\right)^7}{35280}

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∫x+1tan(x)(sin(u)u )du
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