$\left(6x^{2}+26x+32\right):\left(3x+4\right)$
$\frac{d}{dx}\sqrt[2]{x}+\sqrt[2]{y}=36$
$\left(-20\right)\left(-20\right)$
$\frac{\left(x-9\right)}{6}+\frac{3}{2}-\frac{x^2}{3}$
$-5-9-\left(-6\right)+\left(-2\right)+12$
$x^2\:.\:3x^2$
$\frac{15}{3}xy-\frac{2}{6}yx$
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