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(0−a)3\left(0-a\right)^3(0−a)3
limx→2(x2−5x+6x2+3x+2)\lim_{x\to2}\left(\frac{x^2-5x+6}{x^2+3x+2}\right)x→2lim(x2+3x+2x2−5x+6)
2x2 − 3xy = x(2x− 3y)2x^2\:-\:3xy\:=\:x\left(2x-\:3y\right)2x2−3xy=x(2x−3y)
2n+116n+12−4n−4n+1\sqrt[n+1]{2^{n+1}\sqrt{16^{n+1}\sqrt{2^{-4n-4}}}}n+12n+116n+12−4n−4
∫(4(2ex)−4+1(2ex)−4)dx\int\left(\sqrt{\frac{4\sqrt{\left(2e^x\right)^{-4}}+1}{\sqrt{\left(2e^x\right)^{-4}}}}\right)dx∫⎝⎛(2ex)−44(2ex)−4+1⎠⎞dx
−7(−2a+9)-7\left(-2a+9\right)−7(−2a+9)
(−2x2y3+y)2x3y2−x\frac{\left(-2x^2y^3+y\right)}{2x^3y^2-x}2x3y2−x(−2x2y3+y)
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