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f(x)=sin(x)^3cos(x)^3−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫3π22πsin⁡3(x)cos3(x)dx\int_{\frac{3\pi}{2}}^{2\pi}\sin^3\left(x\right)cos^3\left(x\right)dx

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Final answer to the exercise

−sin⁡(2π)2⋅cos⁡(2π)46+−cos⁡(2π)412+sin⁡(3π2)2⋅cos⁡(3π2)46+cos⁡(3π2)412\frac{- \sin\left(2\pi \right)^{2}\cdot \cos\left(2\pi \right)^{4}}{6}+\frac{- \cos\left(2\pi \right)^{4}}{12}+\frac{\sin\left(\frac{3\pi }{2}\right)^{2}\cdot \cos\left(\frac{3\pi }{2}\right)^{4}}{6}+\frac{\cos\left(\frac{3\pi }{2}\right)^{4}}{12}

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