$\frac{d^2}{dx^2}\left(\frac{1}{1-2x}\right)$
$x\left(3x+3\right)\le\left(2x+1\right)^2$
$m.\:\left(7+m\right)\:+7.\:\left(7+m\right)$
$\lim_{x\to-8}\:-\frac{7}{\left(x+8\right)^2}$
$2x-\sqrt{\left(-8x^3+30\right)}$
$x^{-b}$
$8^2-2\cdot4$
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