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Exercise

∫π6π33sec⁡4θ  dθ \int_{\frac{\pi}{6}}^{\frac{\pi}{3}}3\sec^4\theta\:\:d\theta\:

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Final answer to the exercise

3⋅(tan⁡(π3)⋅sec⁡(π3)23+23tan⁡(π3)−(tan⁡(π6)⋅sec⁡(π6)23+23tan⁡(π6)))3\cdot \left(\frac{\tan\left(\frac{\pi }{3}\right)\cdot \sec\left(\frac{\pi }{3}\right)^{2}}{3}+\frac{2}{3}\tan\left(\frac{\pi }{3}\right)- \left(\frac{\tan\left(\frac{\pi }{6}\right)\cdot \sec\left(\frac{\pi }{6}\right)^{2}}{3}+\frac{2}{3}\tan\left(\frac{\pi }{6}\right)\right)\right)

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∫π6 π3 3sec4θ dθ
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