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f(x)=8(2x^2-1)(4x^3-6x+1)^4−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

∫8(2x2−1)(4x3−6x+1)4dx\int8\left(2x^2-1\right)\left(4x^3-6x+1\right)^4dx

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Final answer to the exercise

4(4x3−6x+1)515+C0\frac{4\left(4x^3-6x+1\right)^{5}}{15}+C_0

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∫8(2x2−1)(4x3−6x+1)4dx
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