$-\frac{1}{2}x^3y^2+3x^2z^2+x^3y^2$
$9x^2-42xy+39y^2$
$9\cos^2x-1=0$
$\left(7x^2+27\right)^3$
$\left(2-8a+6a^2\right)^2$
$\frac{60}{5}$
$cos^3\left(x\right)sin\left(x\right)-sin^3\left(x\right)cos\left(x\right)=\frac{sqrt\left(3\right)}{8}$
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