$10,004\cdot5,07$
$25\:+\:-78\:+\:-32\:\cdot\:-12$
$\lim_{x\to+3}\:\frac{1}{x-3}-\frac{1}{x^2-x-6}$
$x^2+10x+35=0$
$3\left(7j\right)$
$t^2x''\left(t\right)-6x\left(t\right)\:=\:0$
$\lim_{x\to0}\left(\frac{5\ln\left(x^2\right)}{x^2-1}\right)$
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