$-32x^4+16x^2+8$
$\frac{dy}{dt}=10$
$-9\:+\:4q\:=\:-9q\:+\:4$
$\lim_{x\to0}\left(x^3\:cos\:\left(\frac{1}{3x}\right)\right)$
$-2^2-4$
$\left(2-6mn\right)\left(6mn+2\right)$
$y'=2y-4$
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