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$x^2\:+\:6x\:+\:13$
$\left(4b+10\right)\left(4b-5\right)$
$4\left(2x\right)^5$
$13+5x^2+\frac{32}{x^2-2}$
$2-\frac{1}{x-1}+\frac{4}{x+2}$
$\left(x+14\right)\left(x-14\right)$
$\left(-24\right)\:-\:\left(-23\right)$
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