$\frac{\left(2x^3-3x^2+5x-4\right)}{x^3-x+1}$
$\left(7u+4\right)+\left(8u+1\right)$
$\frac{d^3}{dx^3}\left(9\right)$
$-28-+18+35-16+-42$
$\int\frac{5x}{x^2-6x+5}dx$
$32x+80x+50$
$\left(x^4-x\right)^4$
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