$2sin^2\theta\:-sin\theta\:=1$
$\frac{dy}{dw}=-10$
$\sqrt[4]{16a^8}b^4$
$\left(n^2+3d^2\right)^2$
$\lim_{h\to0}\left(\frac{-2\left(4+h\right)+\left(4+h\right)^2-8}{h}\right)$
$120\cdot17$
$1+\cot^2\cdot20=\csc^2\cdot20$
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