$x+\left(x\cdot0.19\right)$
$\lim_{x\to0}\left(\frac{\sec\left(x-1\right)}{x}\right)$
$\left(a^2x-by^2\right)^3$
$ni\:sin\left(60\right)\:=\:nr\:sin\left(40\right)$
$\left(2y+7\right)\left(2y-15\right)$
$\frac{\tan\left(x\right)-\sec\left(x\right)}{\sin\left(x\right)-1}=\sec\left(x\right)$
$x^3+x^2-6\cdot x^2+x-1$
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