$x^6-4^3+4$
$x^3+2x^2+5x$
$4-\left(8+12\right)-3$
$\int\frac{t^2+3t+1}{\left(t^2-9\right)\left(t+5\right)}dx$
$\frac{x}{6x-3}+\frac{7}{6x+6}-\frac{1}{2x-2}$
$\int4^{x+1}dx$
$2scosx=-1$
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