$\left(3-5xe^x\right)\left(3x+2\right)$
$x\:+\:10\:\le15$
$\left(4b-5c\right)\left(4b-7c\right)$
$8-1000$
$x+4<-1$
$\frac{d^4}{dx^4}\left(\frac{1}{3x+6}\right)$
$-10\cdot36+10\cdot15$
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