$27a^3-125$
$\left(2a^2+b^3\right)^3$
$\int\frac{x-2}{\left(x^2+3x-4\right)}dx$
$\frac{\left(\tan\:323-\tan\:8\right)}{\left(1+\tan\:323\tan\:8\right)}=-1$
$6p\cdot7p^{2}$
$4-2x<5-4x$
$120-31$
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