$\frac{d}{dx}\:x^2\tan\left(x\right)$
$\left(-35\right)+33-28-\left(-40\right)\left(-15\right)+5+22-32-\left(-10\right)$
$-x+3=x+3$
$52\cdot46$
$( 4 p q - 3 q ) ^ { 2 }$
$\frac{x-1}{3x}-\frac{x+3}{x^{2}}$
$2\cos\left(x\right)\tan\left(x\right)+\csc\left(x\right)$
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